0=49x^2-70x+25

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Solution for 0=49x^2-70x+25 equation: 



0=49x^2-70x+25

We move all terms to the left:

0-(49x^2-70x+25)=0

We add all the numbers together, and all the variables

-(49x^2-70x+25)=0

We get rid of parentheses

-49x^2+70x-25=0

a = -49; b = 70; c = -25;
Δ = b2-4ac
Δ = 702-4·(-49)·(-25)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-70}{-98}=5/7$

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